282.7=3.14(10)r^2

Solution for 282.7=3.14(10)r^2 equation:

282.7=3.14(10)r^2

We move all terms to the left:

282.7-(3.14(10)r^2)=0

We get rid of parentheses

-3.1410r^2+282.7=0

We add all the numbers together, and all the variables

-3.141r^2+282.7=0

a = -3.141; b = 0; c = +282.7;
Δ = b2-4ac
Δ = 02-4·(-3.141)·282.7
Δ = 3551.8428
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{3551.8428}}{2*-3.141}=\frac{0-\sqrt{3551.8428}}{-6.282}
=-\frac{\sqrt{}}{-6.282}
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{3551.8428}}{2*-3.141}=\frac{0+\sqrt{3551.8428}}{-6.282}
=\frac{\sqrt{}}{-6.282}
$